Solve the given puzzle 2

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navjotjsingh

Wise Old Owl
Correct answer has already been posted and there are very few solutions for this problem in the world and yours is not one of them.
 

The_Devil_Himself

die blizzard die! D3?
puzzle 3 answer is:2

logic is to keep on adding the digits till you get a single digit


5+6+2+3+4+6+4+6+5+4+1+5+1=52=>5+2===7
4+6+4+8+6+6+4+9+8+8+2+1+2=68=>6+8=14=>1+4===5
5+4+6+5+4+6+4+6+4+5+6+4+6=65=>6+5=11=>1+1===2

now Don't tell me I solved 3 in a row.
 
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adi007

Youngling
The_Devil_Himself said:
puzzle 3 answer is:2

logic is to keep on adding the digits till you get a single digit


5+6+2+3+4+6+4+6+5+4+1+5+1=52=>5+2===7
4+6+4+8+6+6+4+9+8+8+2+1+2=68=>6+8=14=>1+4===5
5+4+6+5+4+6+4+6+4+5+6+4+6=65=>6+5=11=>1+1===2

now Don't tell me I solved 3 in a row.

you are right!! :sad::(
 

entrana

M$™ Certified Spammer
aww man devil got it again, i knew this was the answer but u just had to post it before mee
 

The_Devil_Himself

die blizzard die! D3?
No class man all the puzzles are damn easy and for a seasoned player like me they are no match.Maybe I should take a break now and let others catch up.
 

piyush gupta

Cyborg Agent
^^ may be u can solve this

Divisible from 1 to 9

Find a number consisting of 9 digits in which each of the digits from 1 to 9 appears only once. This number should satisfy the following requirements:
a. The number should be divisible by 9.
b. If the most right digit is removed, the remaining number should be divisible by 8.
c. If then again the most right digit is removed, the remaining number should be divisible by 7.
d. etc. until the last remaining number of one digit which should be divisible by 1.

copied from a site (I am very new to this puzzling thing) but i likes this a lot
 
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adi007

Youngling
piyush gupta said:
^^ may be u can solve this

Divisible from 1 to 9

Find a number consisting of 9 digits in which each of the digits from 1 to 9 appears only once. This number should satisfy the following requirements:
a. The number should be divisible by 9.
b. If the most right digit is removed, the remaining number should be divisible by 8.
c. If then again the most right digit is removed, the remaining number should be divisible by 7.
d. etc. until the last remaining number of one digit which should be divisible by 1.

copied from a site (I am very new to this puzzling thing) but i likes this a lot
987654321 ????

adi007 said:
Puzzle 4and 5

Here is the 4th puzzle

here is an message written according to some rule.break it:

mncyhalwn lnhzzlt jkbruy gqd xrb hud yaotkm

Here is the 5th puzzle

2267256821 ----->10
8387281215 ----->80
6165728216 ----->?


Bonus: if you are the first to solve both the puzzle, then you will get 3 points instead of 2

Note:state your proof along with the answer.If there are multiple solutions ,then the first 3 unique solutions will be take into regard

Gallery:
Total number of puzzles solved:3
adi007 0 (If nobody solves the puzzle, then it will go to my credit.)
The_Devil_Himself 3
Vyasram 1
aditya.shevade 1
entrana 1

Leading :The_Devil_Himself

New puzzles added.Thread updated
 
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entrana

M$™ Certified Spammer
puzzle 5 ill try
2-2+6-7+2-5+6-8+2-1 = -5, -5*-2 = 10
8-3+8-7+2-8+1-2+1-5 = -5, -5*-20 = 80
6-1+6-5+7-2+8-2+1-6=12, 12*2 = 24
24????
 
OP
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adi007

Youngling
entrana said:
puzzle 5 ill try
2-2+6-7+2-5+6-8+2-1 = -5, -5*-2 = 10
8-3+8-7+2-8+1-2+1-5 = -5, -5*-20 = 80
6-1+6-5+7-2+8-2+1-6=12, 12*2 = 24
24????

how it is -5*-2 ,-5*-20 and 12*2 ?
 
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