If the answer would have been two or three digit maybe i could have solved(without hit and trial) it but the answer is in 6 digits!I think Its only possible with "hit and trial" method
If not, plz explain
After thinking about the problem for a couple of minutes (kinda embarrassed it took that long to get it), I went directly to the answer, no trial and error. Further, I can also tell you that the next lowest number with this property is 571428 and that there are no other numbers less than 10^50 with this property.
What I realized is that I needed to find a repeating fraction such that the number of repeating digits was one less than the number. This would be a prime number, and seven is the lowest number with this property. With this property, every digit in the repeating fraction appears in each place exactly once (i.e. every repeated digit appears as the first digit after the decimal exactly once for n/p where p > n > 0).
Now I wanted to find any occurances where the nth digit followed the 1.5nth digit.
The repeating digits in 1/7 and their corresponding 'n' where the digits are the first digit after the decimal point are:
142857 - repeating digits
132645 - n
n=2 follows n=3, so the lowest number is 285714. Also, n=4 follows n=6, so the next number is 571428.
Out of curiosity, I checked all the prime numbers up to 50. The ones with p-1 repeating digits are:
17, 19, 23, 29, 31, 47
None of these has two adjacent digits with the desired property, so there is no other solution with less than 50 digits.
I'd be curious if there was a way to either prove that no other solutions exist, or determine which prime numbers would have the required relationship. I think other solutions do exist, but I'll write a program to check them any furthur.
If the answer would have been two or three digit maybe i could have solved(without hit and trial) it but the answer is in 6 digits!
If anyone can explain whats written here it would be appreciated(its the solution)
Did you understand the proof above it?Yeah
program is better option for such calculation
Ans is 1?NEW OBJECTIVE QUESTION
View attachment 10109
Also plz explain your answer
(Also you can ask your mathematics related questions or queries
we will try to solve them)
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NEW OBJECTIVE QUESTION
View attachment 10109
Also plz explain your answer
(Also you can ask your mathematics related questions or queries
we will try to solve them)
^ All the conditions have to be satisfied together
yeahAns is 1?
One, and no explanation required I guess.
Another question -
There is a 10-digit number, represented by ABCDEFGHIJ, where each numeral, 0 through 9, is used once. Given the following clues, what is the number?
1) A + D = a square number
2) G + J = a triangle number
3) B + I = an even number
4) E * F = an odd number
5) C * H = a prime number
6) A / G = G / C
7) E + I = B + H
Note: their are more than one answer
ans is 3
sol. their will be 3 intersection points on each of the 4 lines(so they would be collinear), now every point will have 4 points on old lines(I think you will be able understand what I mean) so only one new line be formed form each point
so ans = 6/2 = 3
H cannot be 1As there are more than one answer of the question
we can also try H=1 condition [I get the above answer with condition C=1]
Also can try A=9, G=3, C=1
Hopefully this image will solve your problemplz explain in simple way
i.e how there are 3 intersection points on each of the 4 lines
every point will have 4 points on old lines
Second answer is 9817453260
H cannot be 1
Hopefully this image will solve your problem
*i.imgur.com/AKoD4m1.png
no problemUmm.. I am not sure how can i explain it more properly in words -
new lines are drawn joining the point of intersections of the previous four lines
NEW OBJECTIVE QUESTION
View attachment 10109
Also plz explain your answer
(Also you can ask your mathematics related questions or queries
we will try to solve them)
Absolutely RightIts 3.5
join the centre of the sphere to the point of contact then a right angled triangle will be formed
r/(h-r) = Sin(30)
R=H/3= 3.5
There is a ten-digit mystery number (no leading 0), represented by ABCDEFGHIJ, where each numeral, 0 through 9, is used once. Given the following clues, what is the number?
1) A + B + C + D + E is a multiple of 6.
2) F + G + H + I + J is a multiple of 5.
3) A + C + E + G + I is a multiple of 9.
4) B + D + F + H + J is a multiple of 2.
5) AB is a multiple of 3.
6) CD is a multiple of 4.
7) EF is a multiple of 7.
8) GH is a multiple of 8.
9) IJ is a multiple of 10.
10) FE, HC, and JA are all prime numbers.