OP
Jaskanwar Singh
Aspiring Novelist
no problem nims.
some more?
some more?
IIT-JEE problems
T
The Conqueror
Guest
Subtangent, ordinate and subnormal to y^2 = 4ax at point different from origin are in
a)AP
b)GP
c)HP
d)N/T
a)AP
b)GP
c)HP
d)N/T
OP
Jaskanwar Singh
Aspiring Novelist
i haven't still done the concept of subtangent, subnormal. some other question?
RizEon
Broken In
GP- 2at^2, 2at and 2a... (SN is of constant length for any point)
KDroid
Cyborg Agent
HELP
Prove that infinite number of triangles can be constructed in either of the parabolas y^2 = 4ax and x^2=4by whose sides touch the other parabola.
My maths teacher has announced Rs. 100 reward to anyone who solves this question in our class. If someone @ TDF helps me to do it, I'll give half of that amount to him.
(If my teacher keeps his promise)
Prove that infinite number of triangles can be constructed in either of the parabolas y^2 = 4ax and x^2=4by whose sides touch the other parabola.
My maths teacher has announced Rs. 100 reward to anyone who solves this question in our class. If someone @ TDF helps me to do it, I'll give half of that amount to him.
(If my teacher keeps his promise)AcceleratorX
Youngling
^It's a creative problem and you cannot solve it by a single known method. This is the basic problem of science education in India.
Anyway, this is basically the proof of the quadrature of the parabola. The proof is actually very easy, the implications and applications are actually tough.
Think about it a little, you will get the answer.
Anyway, this is basically the proof of the quadrature of the parabola. The proof is actually very easy, the implications and applications are actually tough.
Think about it a little, you will get the answer.
Last edited:
AcceleratorX
Youngling
I'll give you a hint: Use the fundamental theorem of calculus: Definite integral as limit of a sum. Now what happens when the integral is not limited? It's an infinite series.....
I think this should bring you close enough to the answer.
I think this should bring you close enough to the answer.
OP
Jaskanwar Singh
Aspiring Novelist
guys help with these -
*i.imgur.com/1Pf8I.png
*i.imgur.com/TBUPj.png
*i.imgur.com/Att7l.png
the last one i found by using the answers though!
*i.imgur.com/1Pf8I.png
*i.imgur.com/TBUPj.png
*i.imgur.com/Att7l.png
the last one i found by using the answers though!
OP
Jaskanwar Singh
Aspiring Novelist
yes you are right.
how to do others?? anyone?
how to do others?? anyone?
KDroid
Cyborg Agent
A circle and a rectangular hyperbola meet in four points A, B, C and D. If the line AB passes through the centre of the hyperbola, then CD passes through
(a) Centre of The Hyperbola
(b) Centre of The Circle
(c) Mid-Point of the centres of the Circle and Hyperbola
(d) None of These
(a) Centre of The Hyperbola
(b) Centre of The Circle
(c) Mid-Point of the centres of the Circle and Hyperbola
(d) None of These
thetechfreak
Legend Never Ends
Just found this thread. Will be giving Jee in 2013. Will be a regular visitor now
@kunal is the answer A ?
@kunal is the answer A ?
Last edited:
KDroid
Cyborg Agent
No.. Answer is B. I don't know the Method. I used a Graphing Calculator to verify the Answer.
*www.desmos.com/calculator/2c30153d73 (AB is 5y+4x=0. CD is passing through centre of the Circle)
Another one...
The tangent drawn from (h,k) to an ellipse x^2/a^2 +y^2/b^2 = 1 touches the circle x^2 + y^2 = c^2, then the locus of (h,k) is
(a) Ellipse
(b) Circle
(c) Parabola
(d) None of These
*www.desmos.com/calculator/2c30153d73 (AB is 5y+4x=0. CD is passing through centre of the Circle)
Another one...
The tangent drawn from (h,k) to an ellipse x^2/a^2 +y^2/b^2 = 1 touches the circle x^2 + y^2 = c^2, then the locus of (h,k) is
(a) Ellipse
(b) Circle
(c) Parabola
(d) None of These
OP
Jaskanwar Singh
Aspiring Novelist
guys any link to zener diode characteristic apparatus assembled? i confused with few connections.
hjpotter92
The Boy Who Lived
What kind of question it was/is? Also, have you solved this one?
*i.imgur.com/1Pf8I.png
OP
Jaskanwar Singh
Aspiring Novelist
connecting wires on this, in lab -
*sterlingco.com/admin/RealImage/5710677.jpg
i think (a)
Last edited:
hjpotter92
The Boy Who Lived
The nearest configuration I could find was this:
*www.analog.com/library/analogDialogue/archives/35-02/avoiding/Fig4.gif
As for those questions, I am too lazy to solve them now... Seriously, we get too lazy in colleges.
OK. Tried that problem. The answer IS (a).
Here's a li'l bit of how:
assembling terms:
*i.imgur.com/CuwCw.png
Now, take e^{y} = t, dy/dx = {1/t} {dt/dx}
Hence;
*i.imgur.com/pLV12.png
Solving from here is using Integrating factor and stuff.
*www.analog.com/library/analogDialogue/archives/35-02/avoiding/Fig4.gif
As for those questions, I am too lazy to solve them now... Seriously, we get too lazy in colleges.
OK. Tried that problem. The answer IS (a).
Here's a li'l bit of how:
assembling terms:
*i.imgur.com/CuwCw.png
Now, take e^{y} = t, dy/dx = {1/t} {dt/dx}
Hence;
*i.imgur.com/pLV12.png
Solving from here is using Integrating factor and stuff.