Post mathematic related questions here

OP
rst

rst

Youngling
Average velocity= 72 km/h= 20m/s
Total time= 25s
Total distance= 20*25=500m

Let t1,t2,t3 be time for acceleration, uniform motion and retardation

Time for acceleration and retardation will be same

So t1 +t2+t1= 25
2 t1 + t2 = 25

Velocity after time t1
v1 = 0+5t1


Now we can draw v- t gragh of above motion which will be like trapezium

Distance= area of trapezium
500= 1/2 (t2+25)v1
1000= (25-2t1+25) 5t1
Solving t1=5

So t2=15s
 
Last edited:

powerhoney

Cyborg Agent
Yes answer is correct

Posting the solution below!!! :)

DSC_0134.jpg

- - - Updated - - -

Yes answer is correct

Posting the solution below!!! :)

DSC_0134.jpg


*i.imgur.com/GNIbbJd.jpg?1
 
OP
rst

rst

Youngling
Find the number of all possible selections of one or more questions from 10 given questions, each question having an alternative.

A)3^(10)

B) 2^ (10) -1

C) 3^(10) -1

D) 2^(10 )
 
OP
rst

rst

Youngling
Ans is option (c) 3^10 -1

As for each question we have 3 options
1) do it 2) leave it 3) do alternative question
 
Top Bottom