Guys, I have doubt over this Question. It is from 11th class RD Sharma. Permutation -> Exercise - 16.2 -> Q24.
Below is a part of the Question.
Q. How many 3 digit odd numbers can be formed using 0,3,5,7, repetition not allowed.
Sol. What I did.
_ _ _
3 X 3 X 1
For Hundredth place - It can be filled in 3 ways (any of 3,5,7), we cannot use 0.
For Tens place - It can be filled in 3 ways (0,3,5,7) as one of 3,5,7 already filled in hundredth place).
For Ones place - It can be filled in 1 way as two digits of 3,5,7 already used in above two places and it cannot use 0.
And solution I found on book says this: -
It fills Hundredth first, then Ones and then Second.
*i.imgur.com/T5f2zsO.png
_ _ _
3 X 2 X 2
What is that I'm not understanding or doing wrong??