bits and bytes HELP PLZ!!!

[mediator]

I need a little cleaning up of my bits n bytes confusion!

Facts I know!
1. 1 byte (B) = 8 bits (b)
2 1KB = 1024 b

Now I want to know what is the maximum memory space or frame size a 32 bit system would take ?
I would appreciate a detail and clear explanantion! !

 

[escape7]

same here, see a lot of posts related to 32 bit & 64 bit system etc...gove over my head.

 

[Delta]

1KB = 1024 b

It is 1024 B. Not b.

32 bit memory indicates register size. A 32-bit register meant that 2^32 addresses, or 4 gigabytes of RAM memory.

 

[cyrux]

64 bit can handle lots of RAM 2^64

 

[mediator]

2^32 addresses is fine!
And how do u calculate that 2^32 is 4 GB !
I mean 2^32 = 4294967296 addresses not some RAM size!
So how come 2^32 = 4 GB

 

[QwertyManiac]

the actual length of 4 gb is 4294967296
divide it by (1024)^3

 

[mediator]

I know that! But u still havent figured out what iam trying to ask!
I mean 2^32 = 4294967296 addresses Ok. Lets round off this figure in giga term, So we have 2^32 = 4 giga addresses OK.
Now this is equal to 4 GB RAM if one address space = 1 Byte right.
So does that mean in 32 bit systems 1 address space = 1KB?? I believe not!
So how is 2^32 = 4GB RAM ???????

 

[siriusb]

So does that mean in 32 bit systems 1 address space = 1KB?? I believe not!
So how is 2^32 = 4GB RAM ???????

Watch me when I say, "A 32 bit machine can address upto 4GigaBytes of memory".
Modern computers are byte addressable machines, not bit or kbyte addressable.

 

[mediator]

So does that mean in 32 bit systems 1 address space = 1KB?? I believe not!
So how is 2^32 = 4GB RAM ???????

Watch me when I say, "A 32 bit machine can address upto 4GigaBytes of memory".
Modern computers are byte addressable machines, not bit or kbyte addressable.

I know 32 bit machine can address upto 4 GB memory.
But how do u actually CALCULATE DAT?????

 

[siriusb]

Since no one else is answereing...

But how do u actually CALCULATE DAT?????

U gave the answer to it urself in the previous post: 2^32=4G addresses, with each address pointing to a memory location. Now that u also know that 1 location in memory is 1Byte, 4G addresses can address 4G Bytes. I hope this is what u asked of me.

 

[mediator]

Thanx siriusb Dats was the missing link in my mind!
Dat 1 location in memory is 1Byte.