Official Digit CTC IV discussion thread - Last leg starts 6th Oct 2012

[raviac]

Official Digit CTC IV discussion thread

Got the answerBOND and page124 but even after all the permutatuons ans combinations its not taking the answer in d1 b2 b6 d6 question hence i need a clue or the answer plz!

 

[ant24x7]

Got the answerBOND and page124 but even after all the permutatuons ans combinations its not taking the answer in d1 b2 b6 d6 question hence i need a clue or the answer plz!

Do you know viswanathan anand?

There have always been alternatives to human labor

Yeah actually. I was damn clueless before comparing those files.

 

[Ramcool55]

Got the answerBOND and page124 but even after all the permutatuons ans combinations its not taking the answer in d1 b2 b6 d6 question hence i need a clue or the answer plz!

Read the question slowly again.. You'll understand what's wrong.. The answer you got is correct though

Yeah actually. I was damn clueless before comparing those files.

Yeah... I got the answer... But I'm still clueless as to how I got it.. Weird

 

[Paras Lehana]

Got the answerBOND and page124 but even after all the permutatuons ans combinations its not taking the answer in d1 b2 b6 d6 question hence i need a clue or the answer plz!

The page no u got is wrong

 

[pulkitpopli2004]

any clue for second devworx question..

 

[athulashok]

@ ant24/7 , pls check pm!!

 

[Makx]

any clue for second devworx question..

find something in the folder

 

[sahil333222]

Swooosh finallyCheckpoint 3

 

[pulkitpopli2004]

^^which is the last question?

 

[srcanon]

I'm stuck on the 6th one i.e. -
77(10) = 2x3^3 + 2x3^2 + 1x3^1 + 2x3^0 or 2212(3)

Therefore, 77 = 2212

Applying that same logic

71 = ??
Any clues??

 

[ant24x7]

I'm stuck on the 6th one i.e. -
77(10) = 2x3^3 + 2x3^2 + 1x3^1 + 2x3^0 or 2212(3)

Therefore, 77 = 2212

Applying that same logic

71 = ??
Any clues??

May be little bit math or ternary calculation lead you towards answer

Stuck on Joker. Any hint. Didn't find that racing sim yet.

 

[1RF4N]

I'm stuck on the 6th one i.e. -
77(10) = 2x3^3 + 2x3^2 + 1x3^1 + 2x3^0 or 2212(3)

Therefore, 77 = 2212

Applying that same logic

71 = ??
Any clues??

why 77(10) = 2x3^3(54) + 2x3^2(18) + 1x3^1(3) + 2x3^0(2) ?????

 

[psman]

why 77(10) = 2x3^3(54) + 2x3^2(18) + 1x3^1(3) + 2x3^0(2) ?????

thats a base(10) to base(3) conversion.....so now i think google can do the maths part!!

May be little bit math or ternary calculation lead you towards answer

Stuck on Joker. Any hint. Didn't find that racing sim yet.

its in a rar file...inside the "game engine" folder

 

[srcanon]

thats a base(10) to base(3) conversion.....so now i think google can do the maths part!!



its in a rar file...inside the "game engine" folder

Thanks, I got it.

 

[sp4u]

Who uses muling?plz hlp!

use the board game given at the registration page

 

[Paras Lehana]

Checkpoint 3!!

@ 8:00 PM

 

[srcanon]

Any Clues to this -
And that is the __ number... in song and some games

 

[Shane]

somebody help me to finding the manual ..

 

[Paras Lehana]

somebody help me to finding the manual ..

In a zip file...!!

Zip Name - related to RACING

 

[varunmashru]

Help!!!

Someone help me in that GTA clue!! Thanks in Advance!!