# Maths Quiz

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#### dheeraj_kumar

##### Legen-wait for it-dary!
^^ dont bring in your homework textbook problems... i remember doing that...

#### red_devil

##### Back!
^^ lol from maths quiz to a maths homework solver, this thread is going places

OP

#### Krazzy Warrior

##### "Aal Izz Well"
LOL!

I know the answer..it is a quiz...

#### Edge-of-chaos

##### Broken In
^^ lol from maths quiz to a maths homework solver, this thread is going places

Lets evolve it to "Dump your assignments here!!!"

#### The Conqueror

##### Elevating Humanity
ok try to answer this maths question...itz easy :

Each ship that passes through the Panama Canal requires about 52 million gallons of water to move the ship through the canal from the atlantic ocean to the pacific ocean. If 36 ships passed through the canal, moving from the atlantic ocean to the pacific ocean ,which is closes to the number of gallons of water that was required??

A) 1.9 x 10^5 gallons B) 1.9 x 10^9 Gallons C) 8.8 x 10* gallons D) 8.8 x 10^9 gallons E) None of these

#### MasterMinds

##### hell boy
ans> E

my ques:-

prove that any number raised to power zero is one..!!!

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#### jal_desai

##### In the zone
There is an island. Its inmates speak only two sentences at a time. Out of those two sentences, one is right and one is wrong. You go to that island and meet 4 inmates Ram, Sita, Laxman and Hanuman.

You: Whose wife is Sita?
Ram: Sita is the wife of no one. Sita is married to my brother.
Sita: Laxman is my husband. I am married to Hanuman.
Laxman: Sita is unmarried. Ram is not my brother.
Hanuman: I don't talk with strangers. Sita is not unmarried.

pretty simple. Whose wife is Sita?

^ ^ ^ Hanuman.

#### jal_desai

##### In the zone
^^

Another one:

Imagine you have gone to China (from Chandni Chowk, ofcourse) and you have learnt "talwarbaazi" over there. Now you are faced with a dragon and you are supposed to kill it. The dragon has 3 heads and 3 tails. A dragon is considered dead if ALL heads and ALL tails are chopped off. But this dragon is nasty. Here are the conditions:

2) If 1 tail is chopped off, 2 extra tails grow.
3) If 2 tails are chopped off together, 1 head grows.
4) If 2 heads are chopped off together, nothing grows.

So what is the minimum number of 'slashes' required to kill the dragon?

this is also preety simple. remember "MINIMUM NUMBER OF SLASHES".

no one??

9 slashes.

#### kanishka

##### In the books..Studying
^^

Another one:

Imagine you have gone to China (from Chandni Chowk, ofcourse) and you have learnt "talwarbaazi" over there. Now you are faced with a dragon and you are supposed to kill it. The dragon has 3 heads and 3 tails. A dragon is considered dead if ALL heads and ALL tails are chopped off. But this dragon is nasty. Here are the conditions:

2) If 1 tail is chopped off, 2 extra tails grow.
3) If 2 tails are chopped off together, 1 head grows.
4) If 2 heads are chopped off together, nothing grows.

So what is the minimum number of 'slashes' required to kill the dragon?

this is also preety simple. remember "MINIMUM NUMBER OF SLASHES".

I got the answer.It is damn simple.

1)In First Shot he cut 2 heads together so nothing grows.
Now dragon has 1 head , 3 Tails .
2)next shot he cut 2 tails , so another head grows.
Now 2 heads , 1 tail.
3)He cuts 1 tail so that 2 tails grow.
now 2 heads , 2 tails
4)he cut once again 1 tail so that 2 grows
now 2 heads , 3 tails
5)another 1 tail gone so that 2 tails grow
now 2 heads , 4 Tails
6)He cut 2 tails , 1 head grows
Now 3 heads , 2 tails
7)He cut another 2 tails so 1 head grows
Now 4 head and no Tail
8)He cut 2 heads nothing grows.
Now 2 heads and no tail
9)Again he cut 2 heads and nothing grows.
Now NO HEAD AND NO TAIL!!

Toh mar ke hi mana

Let me shoot you a question.

4_4_4_4=20

using: addition , substraction , Multiplication & Division .Fill in the blanks .

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(4/4 + 4) * 4

#### kanishka

##### In the books..Studying
^good one buddy!

Right!

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