Printf Doubt

[blueshift]

Can you please explain a bit more in detail, how we get 3 2 as output ?

int i=2;
printf("%d %d",i,i++);

When we code like this, the evaluation happens from right to left i.e. first i++ will be done. So for the 2nd %d in printf(), the value of i is still '2'. Then only i is incremented to '3' and displayed in the 1st %d. All this happens during compiling.
If instead the code is:

printf("%d %d", i++, i);

the result is: 2 2
If you use another printf() after this, then it will display i as '3'.

 

[khattam_]

It must give 3 2 as the output coz calaculations are done from right side in printf.
Check again.
I tried in Turbo and GCC.

sorry its

3 2

just a typing mistake.. hope you got what I was tryin to explain...
so you see your earlier explanation was wrong...



Anyways, I've got the answer when I asked in another forum.
*forum.mazzako.com/index.php?topic=13291.0