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Physics Numericals

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Cyborg Agent
Help me with this sum.. got no clue what to do..

Q) A piece of iron of mass 200g and temperature 300 degree C is dropped into 1.00 kg of water of temperature 20 degree C. What will b e the eventual temperature of the water? ( Take c for iron as 470 J/kg and for water as 4200 J/kg ).


mass of iron = 0.2 kg
t of iron = 300c
m of water = 1
initial t of water = 20
let final temp be t2

q released by iron = q absorbed by water.
0.2*470*(300-t2) = 1*4200*(t2-20)

Just simplify and obtain value of t2.
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