8086 programming problem

[gaurav9991]

In 8086 CPU the following register contents are

CS:4100H DS:A000H BX:0350H IP:0100H

The 8086 fetches the following instruction using above register

MOV [BX] , AX

1) Which is the memory address from where the instruction is fetched?

2)Which is the memory address where the data that is in AX is stored?

 

[pulkitpopli2004]

as far as i remember

1. instruction will be fetched from the address present in instruction pointer IP i.e eq to 0100H

2. And AX will be stored at address 0350H

 

[gaurav9991]

as far as i remember

1. instruction will be fetched from the address present in instruction pointer IP i.e eq to 0100H

2. And AX will be stored at address 0350H

i am agree with you for the first answer but for second indirect addressing mode is used. Had it been MOV A,B then it would be 035H
am i correct ?

 

[pulkitpopli2004]

well [BX] tells that the the value of the AX will be stored not in BX bt at the address of BX..
and address of BX is 0350H.. so i think this wud b d only solution

 

[silent008]

In 8086 CPU the following register contents are

CS:4100H DS:A000H BX:0350H IP:0100H

The 8086 fetches the following instruction using above register

MOV [BX] , AX

1) Which is the memory address from where the instruction is fetched?

2)Which is the memory address where the data that is in AX is stored?

I believe that the instructions are fetched from 4200H and the data is stored in A350H.

 

[Jerin]

I think it is 4200 high order address.