IIT-JEE problems

[Jaskanwar Singh]

no problem nims.
some more?

 

[The Conqueror]

Subtangent, ordinate and subnormal to y^2 = 4ax at point different from origin are in
a)AP
b)GP
c)HP
d)N/T

 

[Jaskanwar Singh]

Subtangent, ordinate and subnormal to y^2 = 4ax at point different from origin are in
a)AP
b)GP
c)HP
d)N/T

i haven't still done the concept of subtangent, subnormal. some other question?

 

[RizEon]

Subtangent, ordinate and subnormal to y^2 = 4ax at point different from origin are in
a)AP
b)GP
c)HP
d)N/T

GP- 2at^2, 2at and 2a... (SN is of constant length for any point)

 

[KDroid]

HELP

Prove that infinite number of triangles can be constructed in either of the parabolas y^2 = 4ax and x^2=4by whose sides touch the other parabola.

My maths teacher has announced Rs. 100 reward to anyone who solves this question in our class. If someone @ TDF helps me to do it, I'll give half of that amount to him. (If my teacher keeps his promise)

 

[AcceleratorX]

^It's a creative problem and you cannot solve it by a single known method. This is the basic problem of science education in India.

Anyway, this is basically the proof of the quadrature of the parabola. The proof is actually very easy, the implications and applications are actually tough.

Think about it a little, you will get the answer.

 

[KDroid]

I did not give it a try. Will give it a try tomorrow.

 

[AcceleratorX]

I'll give you a hint: Use the fundamental theorem of calculus: Definite integral as limit of a sum. Now what happens when the integral is not limited? It's an infinite series.....

I think this should bring you close enough to the answer.

 

[Jaskanwar Singh]

guys help with these -

*i.imgur.com/1Pf8I.png
*i.imgur.com/TBUPj.png
*i.imgur.com/Att7l.png

the last one i found by using the answers though!

 

[Windows]

Answer for the last question is (c).

 

[Jaskanwar Singh]

yes you are right.

how to do others?? anyone?

 

[KDroid]

A circle and a rectangular hyperbola meet in four points A, B, C and D. If the line AB passes through the centre of the hyperbola, then CD passes through

(a) Centre of The Hyperbola
(b) Centre of The Circle
(c) Mid-Point of the centres of the Circle and Hyperbola
(d) None of These

 

[thetechfreak]

Just found this thread. Will be giving Jee in 2013. Will be a regular visitor now

@kunal is the answer A ?

 

[KDroid]

No.. Answer is B. I don't know the Method. I used a Graphing Calculator to verify the Answer.

*www.desmos.com/calculator/2c30153d73 (AB is 5y+4x=0. CD is passing through centre of the Circle)

Another one...

The tangent drawn from (h,k) to an ellipse x^2/a^2 +y^2/b^2 = 1 touches the circle x^2 + y^2 = c^2, then the locus of (h,k) is


(a) Ellipse
(b) Circle
(c) Parabola
(d) None of These

 

[pramudit]

ans is parabola....?

 

[KDroid]

No.. Answer is not parabola... The answer key states that it is Ellipse.. But I don't think so.. I think it should be straight line...

 

[Jaskanwar Singh]

guys any link to zener diode characteristic apparatus assembled? i confused with few connections.

 

[hjpotter92]

guys any link to zener diode characteristic apparatus assembled? i confused with few connections.

What kind of question it was/is? Also, have you solved this one?
*i.imgur.com/1Pf8I.png

 

[Jaskanwar Singh]

What kind of question it was/is?

connecting wires on this, in lab -

*sterlingco.com/admin/RealImage/5710677.jpg

Also, have you solved this one?
*i.imgur.com/1Pf8I.png

i think (a)

 

[hjpotter92]

The nearest configuration I could find was this:

*www.analog.com/library/analogDialogue/archives/35-02/avoiding/Fig4.gif

As for those questions, I am too lazy to solve them now... Seriously, we get too lazy in colleges.

OK. Tried that problem. The answer IS (a).

Here's a li'l bit of how:
assembling terms:
*i.imgur.com/CuwCw.png

Now, take e^{y} = t, dy/dx = {1/t} {dt/dx}

Hence;
*i.imgur.com/pLV12.png
Solving from here is using Integrating factor and stuff.