ankurankan
Right off the assembly line
When I run the code:
>>>i=5
>>>def f(arg=i):
print(arg)
>>>i=6
>>>f()
It print 5.Why is this so??
>>>i=5
>>>def f(arg=i):
print(arg)
>>>i=6
>>>f()
It print 5.Why is this so??
Ishu Gupta
Manchester United
In the second line, its read as def f(arg=5):.
If you use f(i), it'll print 6.
If you use f(i), it'll print 6.