How To Prove 1=2

[[A]bu]

No have fun

Let
0=0
or, a^2-a^2=a^2-a^2
or, a(a-a)=(a+a)(a-a) ---in first a is common and in second a^2-b^2 Form...
or, a=a+a--- Cutting (a-a)
or, a=2a
or, 1=2

From this proove any number
have fun and make fun

 

[int86]

cutting by (a-a) means here that you are diividing by 0.
that should result in infinity at both sides.

Cautionlaying with infinity is highly injurious to resoning.

 

[a_k_s_h_a_y]

math noob is here

 

[praka123]

so,with my H500 dataone connection -can i claim double bandwidth

 

[[A]bu]

you should divide both side by (a-a)

 

[Pathik]

^^ arey but (a-a)=0.. and u cant divide any number by 0..
Go learn maths, kid..

 

[[A]bu]

donot suppose any value just let what there is...

 

[Third Eye]

See This

 

[Hustlerr]

math noob is here

Same Here