Binary number in C

[rijinpk1]

Have you put t=~b inside the loop?

Have you put t=~b inside the loop?

 

[harshilsharma63]

That will be a better option. Suppose I take two inputs as 100110. Now the I want to operate the 0th bit of i/p with the 1st bit. And this goes on upto the MSB. The operation can be anything like OR,AND, NOR, NAND, XOR and XNOR. For OR, the desired o/p is 10111. I think now you can understand.

Code -
#include <stdio.h>
#include <string.h>
int main()
{
char b[100],t;
int i,l=0;
scanf("%[^\t\n]s",b); /*scanf to accept multi-word string*/
for(i=0; b!='\0';i++)
{
b-='0';
l++;
}
for(i=0;i<l-1;i++)
{
t=b&b[i+1];
t=!t;
printf("\nNAND: %d", (t));
printf("\n");
}
return 0;
}
The program is working good in case of OR,AND and XOR. But its not giving the proper result while using NOT. If I use the bitwise ~ operator, the o/p is in 2's compliment form.

Using '!' wouldn't work. Create a function for that.

 

[Arnab008]

Ok I will do that.

 

[deepakkrishnan]

Check the image and let me know if this is what you're trying to achieve.

if yes then I believe you can use modulo '%' to achieve all the tasks that you mentioned

 

[Arnab008]

This is the actual thing that I want to do. The o/p will depend on the operator used. Just check it. Its nothing but a simple encoding process.

 

[deepakkrishnan]

try this and check I've not compiled it but should work as per my assumptions.

char i_number[32];
char o_number[32];
int length, a,b;

printf("Enter the binary number : ");
scanf("%s", i_number);

length = strlen(b_number);


// For AND operation;

for (int i = length-1 ; i>0; i++ )
{
			
	if(i_number[i] == '0')
		a = 0;
	else
		a =1;

	if(i_number[i-1] == '0')
		b = 0;
	else
		b = 1;
	
	a = a&b;
	o_number[i] = a;
}

	
	if(i_number[0] == '0')
		a = 0;
	else
		a =1;

	if(i_number[length-1] == '0')
		b = 0;
	else
		b = 1;
	
	a = a&b;
	o_number[i] = a;

 

[Arnab008]

I dont think that this command - "o_number = a;" will work. Still I will check it once.

 

[deepakkrishnan]

As I said I haven't checked it .. so not sure .. ideally it should take it .. as far as my understanding goes

 

[Arnab008]

#include <stdio.h>
#include <string.h>
int main()
{
char i_number[32];
char o_number[32];
int length, a,b,i;
printf("Enter the binary number : ");
scanf("%s",i_number);
length = strlen(i_number);
for (i = length-1 ; i>0; i--)
{
if(i_number == '0')
a = 0;
else
a =1;
if(i_number[i-1] == '0')
b = 0;
else
b = 1;
a = a&b;
a=!a;
o_number = a;
}
if(i_number[0] == '0')
a = 0;
else
a =1;
if(i_number[length-1] == '0')
b = 0;
else
b = 1;

a = a&b;
a=!a;
o_number = a;
for (i=0;i<length;i++)
printf("%d",o_number);
return 0;
}
This is the complete code. Its working. But the complexity time is high in this case, and if we want to do all the operations, time will increase more.

 

[deepakkrishnan]

a=!a;
o_number = a;

for (i=0;i<length;i++)
printf("%d",o_number);
return 0;
}
This is the complete code. Its working. But the complexity time is high in this case, and if we want to do all the operations, time will increase more.

I didn't get why you used "a=!a";
and instead of using a loop to display the output you can directly use "printf("%s" , o_number );

this is the simplest way of implementing .. I am trying to figure out a more efficient way of doing that but it's failing me.. If you're able to crack it then please do share.

 

[Arnab008]

Yeah the loop for printing the o/p is useless. But how to replace '!'? M trying too. I will let u know if I crack the code in an efficient manner.

 

[harshilsharma63]

@OP; create functions for all logical operations rather than embedding the conde in min itself.

 

[deepakkrishnan]

Yeah the loop for printing the o/p is useless. But how to replace '!'? M trying too. I will let u know if I crack the code in an efficient manner.

Why do you want "a=!a;" what are you trying to achieve with this..

@OP; create functions for all logical operations rather than embedding the conde in min itself.

The code i gave was supposed to be implemented in a function.. one can implement 6 functions but that would lead to redundant processing of the following code ... Insights on this are more than welcome

for (i = length-1 ; i>0; i--)
{
if(i_number[i] == '0')
a = 0;
else
a =1;
if(i_number[i-1] == '0')
b = 0;
else
b = 1;

 

[Arnab008]

Its a simple not operation that I want to perform. If a was 1, a=!a will store 0 in it.

 

[deepakkrishnan]

^I got that but y do you want to do that .. any particular reason ..

 

[Arnab008]

Ok. Actually I am working on a program based on crytography. Now to publish a research paper I need to calculate each and every details of it. So I need to calculate for each and every operations.

 

[deepakkrishnan]

ohh ok cool .. all the best for your paper

 

[harshilsharma63]

One more memory saving tip. Use C++ instead of C; this will make the Bool data-type available which is the best for the purpose and is just 1 byte long. Plus, you will bet lower abstraction.

 

[Arnab008]

Okay. Thats good bt m limited with a knowledge about C. I will learn C++ very soon. Then I will try to do the program.