# Post mathematic related questions here

OP

#### rst

##### Youngling
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NEW OBJECTIVE QUESTION

(Also you can ask your mathematics related questions or queries
we will try to solve them)
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you can use following mathematic symbols(just do copy and paste)
£ ω ∴ ∂ Φ γ δ μ σ Є Ø Ω ∩ ≈ ≡ ≈ ≅ ≠ ≤ ≥ • ~ ± ∓ ∤ ◅∈ ∉ ⊆ ⊂ ∪ ⊥ ô ∫ Σ → ∞ Π Δ Ψ Γ ∮ ∇∂ √ °α β γ δ ε ζ η θ ι κ λ ν ξ ο π ρ σ τ υ φ χ ψ
x⁰ ¹ ² ³ ⁴ ⁵ ⁶ ⁷ ⁸ ⁹ ⁺ ⁻ ⁿ
x₀ ₁ ₂ ₃ ₄ ₅ ₆ ₇ ₈ ₉ ₊ ₋

#### Ironman

##### In the zone
i am facing problems in learning vedic maths
is there any forum where i can discuss it ??

OP

#### rst

##### Youngling
Post here
We will try to solve them

OP

#### rst

##### Youngling
----------------------------------------------------------------------------------------------------------------------
NEW OBJECTIVE QUESTION

(Also you can ask your mathematics related questions or queries
we will try to solve them)
----------------------------------------------------------------------------------------------------------------------
you can use following mathematic symbols(just do copy and paste)
£ ω ∴ ∂ Φ γ δ μ σ Є Ø Ω ∩ ≈ ≡ ≈ ≅ ≠ ≤ ≥ • ~ ± ∓ ∤ ◅∈ ∉ ⊆ ⊂ ∪ ⊥ ô ∫ Σ → ∞ Π Δ Ψ Γ ∮ ∇∂ √ °α β γ δ ε ζ η θ ι κ λ ν ξ ο π ρ σ τ υ φ χ ψ
x⁰ ¹ ² ³ ⁴ ⁵ ⁶ ⁷ ⁸ ⁹ ⁺ ⁻ ⁿ
x₀ ₁ ₂ ₃ ₄ ₅ ₆ ₇ ₈ ₉ ₊ ₋

Put x=0,then we get
e=|0 -1 3|
|1 0 -4|
|-3 4 0|

e=0

OP

#### rst

##### Youngling
----------------------------------------------------------------------------------------------------------------------
NEW OBJECTIVE QUESTION

(Also you can ask your mathematics related questions or queries
we will try to solve them)
----------------------------------------------------------------------------------------------------------------------
you can use following mathematic symbols(just do copy and paste)
£ ω ∴ ∂ Φ γ δ μ σ Є Ø Ω ∩ ≈ ≡ ≈ ≅ ≠ ≤ ≥ • ~ ± ∓ ∤ ◅∈ ∉ ⊆ ⊂ ∪ ⊥ ô ∫ Σ → ∞ Π Δ Ψ Γ ∮ ∇∂ √ °α β γ δ ε ζ η θ ι κ λ ν ξ ο π ρ σ τ υ φ χ ψ
x⁰ ¹ ² ³ ⁴ ⁵ ⁶ ⁷ ⁸ ⁹ ⁺ ⁻ ⁿ
x₀ ₁ ₂ ₃ ₄ ₅ ₆ ₇ ₈ ₉ ₊ ₋

#### krazylearner

##### poor little me
I luv dis section !!

OP

#### rst

##### Youngling
----------------------------------------------------------------------------------------------------------------------
NEW OBJECTIVE QUESTION

(Also you can ask your mathematics related questions or queries
we will try to solve them)
----------------------------------------------------------------------------------------------------------------------
you can use following mathematic symbols(just do copy and paste)
£ ω ∴ ∂ Φ γ δ μ σ Є Ø Ω ∩ ≈ ≡ ≈ ≅ ≠ ≤ ≥ • ~ ± ∓ ∤ ◅∈ ∉ ⊆ ⊂ ∪ ⊥ ô ∫ Σ → ∞ Π Δ Ψ Γ ∮ ∇∂ √ °α β γ δ ε ζ η θ ι κ λ ν ξ ο π ρ σ τ υ φ χ ψ
x⁰ ¹ ² ³ ⁴ ⁵ ⁶ ⁷ ⁸ ⁹ ⁺ ⁻ ⁿ
x₀ ₁ ₂ ₃ ₄ ₅ ₆ ₇ ₈ ₉ ₊ ₋

cosα+2cosβ+3cos γ=0-----(1)

sinα+2sinβ+3sinγ=0
isinα+2isinβ+3isinγ=0(multiplying both sides by iota)--------(2)

Adding (1) and (2),we get
e^iα+2e^iβ+3e^iγ=0.

using a³+b³+c³−3abc=(a+b+c)(a²+b²+c²−ab−bc−ca).
e^i3α+8e^i3β+27e^i3γ=6e^i(α+β+γ)=−6

Comparing imaginary parts,we get
sin3α+8sin3β+27sin3γ=0

#### theterminator

##### Wise Old Owl
I have one confusion:
In the question
48÷2*12.

will we do the division first or multiplication first & by what rule??

being from comp sci background , i know that multiplication & division are in the same level of priority but the operation will be performed first when encountered upon going from left to right. Some say to follow BODMAS rule to solve...in that case , what will be the answer to this question
48*2÷12

OP

#### rst

##### Youngling
We will solve this question by BODMAS rule
So 48÷2*12 = 24*12=288

#### theterminator

##### Wise Old Owl
We will solve this question by BODMAS rule
So 48÷2*12 = 24*12=288

& this 48*2÷12

OP

#### theterminator

##### Wise Old Owl
48*2÷12 = 48 *(1/6)=8
but in computer program, multiplication will be performed first coz order of precedence is from left to right in case of operators of same level ( * and / are of same level )

Did you first looked for ÷ sign in your keyboard?

OP

#### rst

##### Youngling
but in computer program, multiplication will be performed first coz order of precedence is from left to right in case of operators of same level ( * and / are of same level )

Well,its also correct
By doing so,you will get the same answer
48*2÷12 =96 ÷12 =8
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From left to right you can do any "D" or "M"
Similar is for addition and subtraction

Last edited:

#### the_conqueror

##### Ambassador of Buzz
sec²x dx/(sec x + tan x )^9/2

OP

#### rst

##### Youngling
sec²x dx/(sec x + tan x )^9/2

put tanx =t
then sex²x dx= dt

∫dt/[t+ √ (1+t²)]^9/2--------(1)

Now let t+ √ (1+t²) =u
clearly 1/u =√ (1+t²) -t

So t =1/2 [u - (1/u)]
dt =1/2 [1+ (1/u²)]du

Using in (1),we get
(1/2)∫du [u ^(-9/2) + u ^(-13/2)]du

Now its easy to solve

#### Niilesh

I have one confusion:
In the question
48÷2*12.

will we do the division first or multiplication first & by what rule??

being from comp sci background , i know that multiplication & division are in the same level of priority but the operation will be performed first when encountered upon going from left to right. Some say to follow BODMAS rule to solve...in that case , what will be the answer to this question
48*2÷12

Since there is no bracket 48÷2*12 = 24*12 = 288 = 48*12÷2 = 12÷2*48

OP

#### rst

##### Youngling
View attachment 12070
With AO || CD, find area of shaded region.

∠O=<D=θ (corresponding angles)
Then <ODC= π-θ
The area of the shaded region = the area of the sector OCB - the area of the
triangle OCD

Let <BOC =x and <OCD =y

sin(π−θ)/R=siny/ℓ
sinθ/R=siny/ℓ
y= arcsin(ℓsinθ/R)

x+y+(π−θ)=π
x=θ-y
x=θ-arcsin(ℓsinθ/R)

A(ΔOCD)=(1/2)Rℓsinx

OP

#### rst

##### Youngling
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NEW OBJECTIVE QUESTION